Hereof, how do you find the frequency of a photon given the wavelength?
The energy E, frequency f, and wavelength λ of a Photon are related as follows: E=hf=hc/λ, where c is the speed of light and h is Planck's constant. So, given any one, the other two can be easily calculated. (This is assuming the photon is propagating in a vacuum.
Subsequently, question is, what happens as the frequency of photons increases? An increase in frequency produces a proportional decrease in the wavelength of light with a corresponding increase in the energy of the photons that make up the light. Thus as frequency increases (with a corresponding decrease in wavelength), the photon energy increases and visa versa.
Considering this, what is the frequency of a photon?
Substituting h with its value in J⋅s and f with its value in hertz gives the photon energy in joules. Therefore, the photon energy at 1 Hz frequency is 6.62606957 × 10−34 joules or 4.135667516 × 10−15 eV. is used where h is Planck's constant and the Greek letter ν (nu) is the photon's frequency.
What happens when the wavelength of a photon increases?
That means that increasing the wavelength decreases the light's frequency. Therefore, as the wavelength of a photon increases, its energy decreases.